A <transformer spec> has the following form:
(syntax-rules <literals> <syntax rule> ...)
Syntax: <Literals> is a list of identifiers and each <syntax rule> should be of the form
(<pattern> <template>)
The <pattern> in a <syntax rule> is a list <pattern> that begins with the keyword for the macro.
A <pattern> is either an identifier, a constant, or one of the following
(<pattern> ...) (<pattern> <pattern> ... . <pattern>) (<pattern> ... <pattern> <ellipsis>) #(<pattern> ...) #(<pattern> ... <pattern> <ellipsis>)
and a template is either an identifier, a constant, or one of the following
(<element> ...) (<element> <element> ... . <template>) #(<element> ...)
where an <element> is a <template> optionally followed by an <ellipsis> and an <ellipsis> is the identifier "..." (which cannot be used as an identifier in either a template or a pattern).
Semantics: An instance of syntax-rules produces a new macro transformer by specifying a sequence of hygienic rewrite rules. A use of a macro whose keyword is associated with a transformer specified by syntax-rules is matched against the patterns contained in the <syntax rule>s, beginning with the leftmost <syntax rule>. When a match is found, the macro use is transcribed hygienically according to the template.
An identifier that appears in the pattern of a <syntax rule> is a pattern variable, unless it is the keyword that begins the pattern, is listed in <literals>, or is the identifier "...". Pattern variables match arbitrary input elements and are used to refer to elements of the input in the template. It is an error for the same pattern variable to appear more than once in a <pattern>.
The keyword at the beginning of the pattern in a <syntax rule> is not involved in the matching and is not considered a pattern variable or literal identifier.
Rationale: The scope of the keyword is determined by the expression or syntax definition that binds it to the associated macro transformer. If the keyword were a pattern variable or literal identifier, then the template that follows the pattern would be within its scope regardless of whether the keyword were bound by let-syntax or by letrec-syntax.
Identifiers that appear in <literals> are interpreted as literal identifiers to be matched against corresponding subforms of the input. A subform in the input matches a literal identifier if and only if it is an identifier and either both its occurrence in the macro expression and its occurrence in the macro definition have the same lexical binding, or the two identifiers are equal and both have no lexical binding.
A subpattern followed by ... can match zero or more elements of the input. It is an error for ... to appear in <literals>. Within a pattern the identifier ... must follow the last element of a nonempty sequence of subpatterns.
More formally, an input form F matches a pattern P if and only if:
It is an error to use a macro keyword, within the scope of its binding, in an expression that does not match any of the patterns.
When a macro use is transcribed according to the template of the matching <syntax rule>, pattern variables that occur in the template are replaced by the subforms they match in the input. Pattern variables that occur in subpatterns followed by one or more instances of the identifier ... are allowed only in subtemplates that are followed by as many instances of .... They are replaced in the output by all of the subforms they match in the input, distributed as indicated. It is an error if the output cannot be built up as specified.
Identifiers that appear in the template but are not pattern variables or the identifier ... are inserted into the output as literal identifiers. If a literal identifier is inserted as a free identifier then it refers to the binding of that identifier within whose scope the instance of syntax-rules appears. If a literal identifier is inserted as a bound identifier then it is in effect renamed to prevent inadvertent captures of free identifiers.
As an example, if let and cond are defined as in section 7.3 then they are hygienic (as required) and the following is not an error.
(let ((=> #f)) (cond (#t => 'ok))) => ok
The macro transformer for cond recognizes => as a local variable, and hence an expression, and not as the top-level identifier =>, which the macro transformer treats as a syntactic keyword. Thus the example expands into
(let ((=> #f)) (if #t (begin => 'ok)))
instead of
(let ((=> #f)) (let ((temp #t)) (if temp ('ok temp))))
which would result in an invalid procedure call.