I have one question about Curry.
I have two patterns
parse s | s =:= <first pattern> = ...
parse s | s =:= <second pattern> = ...
I want, the second match work only if the first match failed. But in fact it don't dependence. If I do:
parse s | s =:= <first pattern> = ...
parse s | (s =:= <first pattern>) =:= failed & s =:= <second pattern> = ...
this is don't work - the second pattern don't match if s =:= <first pattern> march or no.
If I do:
parse s | (s =:= <first pattern>) == success = ...
(s =:= <second pattern>) == success = ...
where ...
also bad: if first pattern fail, the second don't call.
How to me to make so that the second match worked in only case when its condition is satisfied, and the second match simultaneously fails?
Best regards,
Rushan Gilmullin
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Received on Do Apr 16 2009 - 09:11:13 CEST